49k^2+112k+64=0

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Solution for 49k^2+112k+64=0 equation: 



49k^2+112k+64=0

a = 49; b = 112; c = +64;
Δ = b2-4ac
Δ = 1122-4·49·64
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{-112}{98}=-1+1/7$

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